1. Вычислите: a) \(\frac{7}{6}-\frac{5}{15}\); б) \((\frac{2}{3}-\frac{4}{9})\cdot \frac{3}{8}\); в) \(\frac{2}{7}+\frac{3}{8}:\frac{7}{32}\); г) \(\frac{5}{12}\cdot (\frac{1}{5}+\frac{3}{25})\)

a) \(\frac{7}{6}-\frac{5}{15}\) = \(\frac{7*5}{6*5}-\frac{5*2}{15*2}\) = \(\frac{35}{30}-\frac{10}{30}\) = \(\frac{25}{30}\) = \(\frac{5}{6}\)

б) \((\frac{2}{3}-\frac{4}{9})\cdot \frac{3}{8}\) = \((\frac{2*3}{3*3}-\frac{4}{9})\cdot \frac{3}{8}\) = \((\frac{6}{9}-\frac{4}{9})\cdot \frac{3}{8}\) = \(\frac{2}{9}\cdot \frac{3}{8}\) = \(\frac{2*3}{9*8}\) = \(\frac{6}{72}\) = \(\frac{1}{12}\)

в) \(\frac{2}{7}+\frac{3}{8}:\frac{7}{32}\) = \(\frac{2}{7}+\frac{3}{8}\cdot \frac{32}{7}\) = \(\frac{2}{7}+\frac{3*32}{8*7}\) = \(\frac{2}{7}+\frac{3*4}{7}\) = \(\frac{2}{7}+\frac{12}{7}\) = \(\frac{14}{7}\) = 2

г) \(\frac{5}{12}\cdot (\frac{1}{5}+\frac{3}{25})\) = \(\frac{5}{12}\cdot (\frac{1*5}{5*5}+\frac{3}{25})\) = \(\frac{5}{12}\cdot (\frac{5}{25}+\frac{3}{25})\) = \(\frac{5}{12}\cdot \frac{8}{25}\) = \(\frac{5*8}{12*25}\) = \(\frac{40}{300}\) = \(\frac{2}{15}\)

Ответ: а) \(\frac{5}{6}\); б) \(\frac{1}{12}\); в) 2; г) \(\frac{2}{15}\)