$$3\frac{3}{8} \cdot \frac{1}{6} + 3\frac{1}{5} \cdot \frac{5}{12} - 4\frac{1}{6} \cdot 3\frac{1}{5} = \frac{27}{8} \cdot \frac{1}{6} + \frac{16}{5} \cdot \frac{5}{12} - \frac{25}{6} \cdot \frac{16}{5} = \frac{27 \cdot 1}{8 \cdot 6} + \frac{16 \cdot 5}{5 \cdot 12} - \frac{25 \cdot 16}{6 \cdot 5} = \frac{27}{48} + \frac{16}{12} - \frac{400}{30} = \frac{9}{16} + \frac{4}{3} - \frac{40}{3} = \frac{9}{16} + \frac{4 - 40}{3} = \frac{9}{16} - \frac{36}{3} = \frac{9}{16} - 12 = \frac{9 - 12 \cdot 16}{16} = \frac{9 - 192}{16} = \frac{-183}{16} = -11\frac{7}{16} $$
Ответ: $$-11\frac{7}{16}$$