Вычислите: $$\left(\frac{5}{6}\right)^2 \cdot 6^3 - \left(\frac{4}{5}\right)^3 \cdot 3\frac{29}{32} = $$

Решим пример по действиям: 1. $$\left(\frac{5}{6}\right)^2 = \frac{5^2}{6^2} = \frac{25}{36}$$ 2. $$6^3 = 6 \cdot 6 \cdot 6 = 216$$ 3. $$\frac{25}{36} \cdot 216 = \frac{25 \cdot 216}{36} = \frac{25 \cdot 6}{1} = 150$$ 4. $$\left(\frac{4}{5}\right)^3 = \frac{4^3}{5^3} = \frac{64}{125}$$ 5. $$3\frac{29}{32} = \frac{3 \cdot 32 + 29}{32} = \frac{96 + 29}{32} = \frac{125}{32}$$ 6. $$\frac{64}{125} \cdot \frac{125}{32} = \frac{64 \cdot 125}{125 \cdot 32} = \frac{2 \cdot 1}{1 \cdot 1} = 2$$ 7. $$150 - 2 = 148$$ Ответ: 148