Вариант 1. Задание 4. Вычислите: а) |8\frac{1}{3}| + |3\frac{2}{3}|; б) |4\frac{1}{6}| - |-2\frac{3}{4}|; в) |-4\frac{3}{5}| \cdot |3\frac{3}{4}|; г) |-5| : |3\frac{1}{7}|;

Решение: a) $$|8\frac{1}{3}| + |3\frac{2}{3}| = 8\frac{1}{3} + 3\frac{2}{3} = 8 + \frac{1}{3} + 3 + \frac{2}{3} = 11 + \frac{1+2}{3} = 11 + \frac{3}{3} = 11 + 1 = 12$$ б) $$|4\frac{1}{6}| - |-2\frac{3}{4}| = 4\frac{1}{6} - 2\frac{3}{4} = \frac{25}{6} - \frac{11}{4} = \frac{50}{12} - \frac{33}{12} = \frac{17}{12} = 1\frac{5}{12}$$ в) $$|-4\frac{3}{5}| \cdot |3\frac{3}{4}| = 4\frac{3}{5} \cdot 3\frac{3}{4} = \frac{23}{5} \cdot \frac{15}{4} = \frac{23 \cdot 15}{5 \cdot 4} = \frac{23 \cdot 3}{4} = \frac{69}{4} = 17\frac{1}{4}$$ г) $$|-5| : |3\frac{1}{7}| = 5 : 3\frac{1}{7} = 5 : \frac{22}{7} = 5 \cdot \frac{7}{22} = \frac{35}{22} = 1\frac{13}{22}$$