Решение:

а) $$\frac{17-12x}{x} - \frac{10-x}{x} = \frac{17-12x - (10-x)}{x} = \frac{17-12x - 10 + x}{x} = \frac{7-11x}{x}$$

Ответ: $$\frac{7-11x}{x}$$

б) $$\frac{12p-1}{3p^2} - \frac{1-3p}{3p^2} = \frac{12p-1 - (1-3p)}{3p^2} = \frac{12p-1 - 1 + 3p}{3p^2} = \frac{15p-2}{3p^2}$$

Ответ: $$\frac{15p-2}{3p^2}$$

в) $$\frac{6y-3}{5y} - \frac{y+2}{5y} = \frac{6y-3 - (y+2)}{5y} = \frac{6y-3 - y - 2}{5y} = \frac{5y-5}{5y} = \frac{5(y-1)}{5y} = \frac{y-1}{y}$$

Ответ: $$\frac{y-1}{y}$$

г) $$\frac{3p-q}{5p} - \frac{2p+6q}{5p} + \frac{p-4q}{5p} = \frac{3p-q - (2p+6q) + (p-4q)}{5p} = \frac{3p-q - 2p - 6q + p - 4q}{5p} = \frac{2p - 11q}{5p}$$

Ответ: $$\frac{2p - 11q}{5p}$$

д) $$\frac{5c-2d}{4c} - \frac{3d}{4c} + \frac{d-5c}{4c} = \frac{5c-2d - 3d + d - 5c}{4c} = \frac{-4d}{4c} = -\frac{d}{c}$$

Ответ: $$\frac{-d}{c}$$

e) $$\frac{2a}{b} - \frac{1-6a}{b} + \frac{13-8a}{b} = \frac{2a - (1-6a) + (13-8a)}{b} = \frac{2a - 1 + 6a + 13 - 8a}{b} = \frac{12}{b}$$

Ответ: $$\frac{12}{b}$$