Решение:
- \(\frac{x^2}{(x-5)^2} - \frac{25}{(5-x)^2} = \frac{x^2}{(x-5)^2} - \frac{25}{(x-5)^2} = \frac{x^2-25}{(x-5)^2} = \frac{(x-5)(x+5)}{(x-5)^2} = \frac{x+5}{x-5}\)
- \(\frac{x^2+25}{(x-5)^3} + \frac{10x}{(5-x)^3} = \frac{x^2+25}{(x-5)^3} + \frac{10x}{-(x-5)^3} = \frac{x^2+25}{(x-5)^3} - \frac{10x}{(x-5)^3} = \frac{x^2+25-10x}{(x-5)^3} = \frac{(x-5)^2}{(x-5)^3} = \frac{1}{x-5}\)
Ответ: а) (x+5)/(x-5); б) 1/(x-5).