Решение задания 1

1. а) $$10\sqrt{3}-4\sqrt{48}-\sqrt{75} = 10\sqrt{3}-4\sqrt{16\cdot 3}-\sqrt{25\cdot 3} = 10\sqrt{3}-4\cdot 4\sqrt{3}-5\sqrt{3} = 10\sqrt{3}-16\sqrt{3}-5\sqrt{3} = -11\sqrt{3}$$.
2. б) $$(5\sqrt{2}-\sqrt{18})\sqrt{2} = (5\sqrt{2}-\sqrt{9\cdot 2})\sqrt{2} = (5\sqrt{2}-3\sqrt{2})\sqrt{2} = 2\sqrt{2}\cdot \sqrt{2} = 2\cdot 2 = 4$$.
3. в) $$(3-\sqrt{2})^2 = 3^2 - 2\cdot 3\cdot \sqrt{2} + (\sqrt{2})^2 = 9 - 6\sqrt{2} + 2 = 11 - 6\sqrt{2}$$.

Ответ: а) $$-11\sqrt{3}$$; б) $$4$$; в) $$11 - 6\sqrt{2}$$.