2) Упростите выражение: $$\frac{16}{x-4} - \frac{x^2}{x-4}$$

$$\frac{16}{x-4} - \frac{x^2}{x-4} = \frac{16-x^2}{x-4} = \frac{(4-x)(4+x)}{x-4} = \frac{-(x-4)(4+x)}{x-4} = -(4+x) = -4-x$$ Ответ: $$-4-x$$