Ответ: -24
\[x^2 - 2x - 8 = 0\]
\[D = b^2 - 4ac = (-2)^2 - 4(1)(-8) = 4 + 32 = 36\]
\[x_1 = \frac{-b + \sqrt{D}}{2a} = \frac{2 + \sqrt{36}}{2(1)} = \frac{2 + 6}{2} = \frac{8}{2} = 4\]
\[x_2 = \frac{-b - \sqrt{D}}{2a} = \frac{2 - \sqrt{36}}{2(1)} = \frac{2 - 6}{2} = \frac{-4}{2} = -2\]
-24
Ответ: -24