Solve the following equation: $$\frac{7x+28}{42} = \frac{18x-12}{42}$$

Here's how to solve the equation step-by-step: 1. Multiply both sides by 42 to eliminate the denominators: $$42 \cdot \frac{7x+28}{42} = 42 \cdot \frac{18x-12}{42}$$ This simplifies to: $$7x + 28 = 18x - 12$$ 2. Move the terms with x to one side and the constants to the other side: Subtract 7x from both sides: $$7x + 28 - 7x = 18x - 12 - 7x$$ $$28 = 11x - 12$$ Add 12 to both sides: $$28 + 12 = 11x - 12 + 12$$ $$40 = 11x$$ 3. Solve for x by dividing both sides by 11: $$\frac{40}{11} = \frac{11x}{11}$$ $$x = \frac{40}{11}$$ Therefore, the solution to the equation is: $$\boxed{x = \frac{40}{11}}$$ Answer: x = 40/11