$$\begin{aligned}9x^2 - 7(4x - x^2 + 16 - 4x) - (1 - 8x + 16x^2) &= 15 \\9x^2 - 7(16 - x^2) - 1 + 8x - 16x^2 &= 15 \\9x^2 - 112 + 7x^2 - 1 + 8x - 16x^2 &= 15 \\-112 - 1 - 15 + 9x^2 + 7x^2 - 16x^2 + 8x &= 0 \\-128 + 8x &= 0 \\8x &= 128 \\x &= \frac{128}{8} \\x &= 16\end{aligned}$$
Ответ: x=16