1) Решить уравнения
1.
$$ \frac{x+2}{3} = 4x - \frac{x+5}{2} $$ $$ \frac{x+2}{3} = \frac{8x - (x+5)}{2} $$ $$ \frac{x+2}{3} = \frac{7x-5}{2} $$ $$ 2(x+2) = 3(7x-5) $$ $$ 2x + 4 = 21x - 15 $$ $$ 19x = 19 $$ $$ x = 1 $$Ответ: $$x = 1$$
2.
$$ \frac{3a-5}{4} + \frac{6}{8} = 2a - \frac{1-a}{2} $$ $$ \frac{3a-5}{4} + \frac{3}{4} = 2a - \frac{1-a}{2} $$ $$ \frac{3a-5+3}{4} = \frac{4a - (1-a)}{2} $$ $$ \frac{3a-2}{4} = \frac{5a-1}{2} $$ $$ 3a - 2 = 2(5a-1) $$ $$ 3a - 2 = 10a - 2 $$ $$ 7a = 0 $$ $$ a = 0 $$Ответ: $$a = 0$$