127. r) arcsin (-1) + arccos \frac{\sqrt{3}}{2};

r) arcsin(-1) + arccos $$\frac{\sqrt{3}}{2}$$ = $$\frac{-\pi}{2} + \frac{\pi}{6}$$ = $$\frac{-3\pi + \pi}{6}$$ = $$\frac{-2\pi}{6}$$ = $$\frac{-\pi}{3}$$.

Ответ: $$\frac{-\pi}{3}$$