128. г) arctg \frac{1}{\sqrt{3}} + arctg √3.

r) arctg $$\frac{1}{\sqrt{3}}$$ + arctg √3 = $$\frac{\pi}{6} + \frac{\pi}{3}$$ = $$\frac{\pi + 2\pi}{6}$$ = $$\frac{3\pi}{6}$$ = $$\frac{\pi}{2}$$.

Ответ: $$\frac{\pi}{2}$$