7) $$ \frac{p^3-1}{1-p^2} = \frac{(p-1)(p^2+p+1)}{(1-p)(1+p)} = \frac{-(1-p)(p^2+p+1)}{(1-p)(1+p)} = \frac{-(p^2+p+1)}{1+p} $$
Ответ: $$\frac{-(p^2+p+1)}{1+p}$$