Освободитесь от иррациональности в знаменателе дроби: a) $$rac{2}{\sqrt{2}}$$ b) $$rac{4}{2\sqrt{2}}$$ c) $$rac{4}{3\sqrt{2}}$$ d) $$rac{1}{\sqrt{2}\sqrt{2}}$$

a) $$rac{2}{\sqrt{2}} = \frac{2 \cdot \sqrt{2}}{\sqrt{2} \cdot \sqrt{2}} = \frac{2\sqrt{2}}{2} = \sqrt{2}$$

b) $$rac{4}{2\sqrt{2}} = \frac{2}{\sqrt{2}} = \sqrt{2}$$

c) $$rac{4}{3\sqrt{2}} = \frac{4\sqrt{2}}{3\sqrt{2}\sqrt{2}} = \frac{4\sqrt{2}}{3 \cdot 2} = \frac{4\sqrt{2}}{6} = \frac{2\sqrt{2}}{3}$$

d) $$rac{1}{\sqrt{2}\sqrt{2}} = \frac{1}{2}$$