Вопрос:
О) (\(\frac{2}{15}+1\frac{7}{12}\))\(\cdot\)\(\frac{30}{103}\)-2:2\(\frac{1}{4}\)\(\cdot\)\(\frac{1}{32}\)\(\cdot\)\(\frac{9}{4}\)
Ответ:
Решение:
- \( 1\frac{7}{12} = \frac{19}{12} \)
- \( \frac{2}{15} + \frac{19}{12} = \frac{2\cdot4 + 19\cdot5}{60} = \frac{8+95}{60} = \frac{103}{60} \)
- \( \frac{103}{60} \cdot \frac{30}{103} = \frac{103\cdot30}{60\cdot103} = \frac{1}{2} \)
- \( 2\frac{1}{4} = \frac{9}{4} \)
- \( 2 : \frac{9}{4} = 2 \cdot \frac{4}{9} = \frac{8}{9} \)
- \( \frac{1}{2} - \frac{8}{9} \cdot \frac{1}{32} \cdot \frac{9}{4} = \frac{1}{2} - \frac{8\cdot1\cdot9}{9\cdot32\cdot4} = \frac{1}{2} - \frac{1\cdot1\cdot1}{1\cdot4\cdot4} = \frac{1}{2} - \frac{1}{16} \)
- \( \frac{1}{2} - \frac{1}{16} = \frac{8}{16} - \frac{1}{16} = \frac{7}{16} \)
Ответ: \(\frac{7}{16}\)
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