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МатематикаВопрос:
М) \(\frac{3}{4}\cdot\frac{5}{6}+2\frac{1}{2}\cdot\frac{2}{5}-1:1\frac{1}{9}\)
Ответ:
Решение:
- \( \frac{3}{4} \cdot \frac{5}{6} = \frac{15}{24} = \frac{5}{8} \)
- \( 2\frac{1}{2} = \frac{5}{2} \)
- \( \frac{5}{2} \cdot \frac{2}{5} = \frac{10}{10} = 1 \)
- \( 1\frac{1}{9} = \frac{10}{9} \)
- \( 1 : \frac{10}{9} = 1 \cdot \frac{9}{10} = \frac{9}{10} \)
- \( \frac{5}{8} + 1 - \frac{9}{10} = \frac{5\cdot5 + 40 - 9\cdot4}{40} = \frac{25 + 40 - 36}{40} = \frac{29}{40} \)
Ответ: \(\frac{29}{40}\)
Похожие
- A) 14-\(10-\frac{11}{13}-5-\frac{9}{13}\)\(\cdot\) 2
- Б) 4\(\frac{2}{21}\)\(\cdot\) 10-19\(\frac{20}{21}\)
- Г) 24\(\frac{8}{41}\)-18\(\frac{6}{41}\):3
- E) \(\frac{27\frac{3}{8}-21\frac{7}{20}}{3\frac{4}{7}-1\frac{23}{28}-(1\frac{47}{65}-\frac{29}{130})}\)
- Ж) \(\frac{7\frac{1}{2}\cdot2\frac{2}{3}-12\frac{3}{4}:1\frac{1}{2}+\frac{3}{8}+2\frac{3}{4}}{110:\frac{3}{5}+24:\frac{2}{5}}\)
- И) \(3\frac{1}{4}+2\frac{1}{6}\):\(\frac{3}{5}\)-2\(\frac{2}{3}\)\(\cdot\)2\(\frac{1}{4}\)+5\(\frac{1}{6}\)
- К) [3\(\frac{1}{4}\)\(\cdot\)\(14\frac{4}{5}+4\frac{4}{15}\)-47]:5\(\frac{9}{10}\)
- О) (\(\frac{2}{15}+1\frac{7}{12}\))\(\cdot\)\(\frac{30}{103}\)-2:2\(\frac{1}{4}\)\(\cdot\)\(\frac{1}{32}\)\(\cdot\)\(\frac{9}{4}\)
- P) 3\(\frac{1}{8}\):[\(\frac{5}{12}-2\frac{13}{24}\)\(\cdot\)\(\frac{4}{7}\)+\(\frac{1}{18}-2\frac{7}{12}\)\(\cdot\)\(\frac{10}{17}\)]
- С) 2\(\frac{3}{4}\):[(\(\frac{5}{7}-1\frac{11}{14}\))\(\cdot\)\(\frac{2}{3}\)+\(\frac{2}{9}-1\frac{5}{6}\)\(\cdot\)\(\frac{18}{25}\)]
- У) \(\frac{\frac{7}{15}+\frac{14}{45}+\frac{2}{9}\cdot10-\frac{1}{3}-\frac{1}{11}\cdot(2\frac{2}{3}-1\frac{3}{4})}{(\frac{3}{7}:\frac{1}{4})\cdot\frac{3}{28}-1}\)
- X) [(\(\frac{5}{6}-\frac{3}{8}\)):\(\frac{3}{4}\)-(\(\frac{3}{8}+\frac{7}{20}\))\(\cdot\)\(\frac{9}{20}\)]:\(\frac{1}{50}\)
