1130. Найдите значение выражения: 1) (2\frac{13}{48}-(-2\frac{5}{12})):(-3\frac{3}{4})+9\frac{3}{4}: (-13); 2) (1\frac{2}{3}-3,6):(-2\frac{7}{9}+4\frac{1}{15})\cdot (-2,6).

Решение: 1) $$(2\frac{13}{48}-(-2\frac{5}{12})):(-3\frac{3}{4})+9\frac{3}{4}: (-13) = (2\frac{13}{48}+2\frac{20}{48}):(-\frac{15}{4})+\frac{39}{4}: (-13) = 5\frac{33}{48}:(-\frac{15}{4})+\frac{39}{4}: (-13) = \frac{273}{48} \cdot (-\frac{4}{15}) + \frac{39}{4} \cdot (-\frac{1}{13}) = -\frac{91}{60} - \frac{3}{4} = -\frac{91}{60} - \frac{45}{60} = -\frac{136}{60} = -2\frac{16}{60} = -2\frac{4}{15}$$; 2) $$(1\frac{2}{3}-3,6):(-2\frac{7}{9}+4\frac{1}{15})\cdot (-2,6) = (1\frac{2}{3}-3\frac{6}{10}):(-2\frac{35}{45}+4\frac{3}{45})\cdot (-2,6) = (1\frac{2}{3}-3\frac{3}{5}):(1\frac{-32}{45})\cdot (-2,6) = (1\frac{10}{15}-3\frac{9}{15}):(-\frac{13}{45})\cdot (-2,6) = -1\frac{14}{15}:(-\frac{13}{45})\cdot (-2,6) = -\frac{29}{15} \cdot (-\frac{45}{13}) \cdot (-2,6) = \frac{29}{15} \cdot \frac{45}{13} \cdot (-2,6) = \frac{29}{1} \cdot \frac{3}{13} \cdot (-2,6) = \frac{29 \cdot 3 \cdot (-2,6)}{13} = \frac{29 \cdot 3 \cdot (-0,2)}{1} = -17,4$$. Ответ: 1) -2\frac{4}{15}; 2) -17,4.