Упростим выражение:
\[\left(\frac{x^2}{2a^3}\right)^3 \cdot \left(\frac{4a^4}{x^5}\right)^2 = \frac{x^6}{8a^9} \cdot \frac{16a^8}{x^{10}} = \frac{2}{1} \cdot \frac{x^6}{x^{10}} \cdot \frac{a^8}{a^9} = 2 \cdot \frac{1}{x^4} \cdot \frac{1}{a} = \frac{2}{x^4a}\]
Подставим значения a = \[-\frac{1}{13}\] и x = -0.31:
\[\frac{2}{(-0.31)^4 \cdot (-\frac{1}{13})} = \frac{2}{0.009235 \cdot (-\frac{1}{13})} = \frac{2}{-0.00071} \approx -2816.9\]
Ответ: -2816.9