17. Найдите корень уравнения logo, (2x-3) + logo.27 logo, 28.

$$log_{0,2}(2x-3) + log_{0,2}7 = log_{0,2}28$$

$$log_{0,2}((2x-3)\cdot 7) = log_{0,2}28$$

$$(2x-3)\cdot 7 = 28$$

$$2x-3 = \frac{28}{7}$$

$$2x-3 = 4$$

$$2x = 4 + 3$$

$$2x = 7$$

$$x = \frac{7}{2} = 3,5$$

Ответ: 3,5