25) 2*\(\frac{2}{5}z+1\)+3\(\frac{1}{3}\)=4*\(\frac{4}{5}z-1\).

Преобразуем смешанные дроби в неправильные: 2*\(\frac{2}{5}z+1\)+\(\frac{10}{3}\)=4*\(\frac{4}{5}z-1\).
Раскроем скобки: \(\frac{4}{5}\)z+2+\(\frac{10}{3}\)=\(\frac{16}{5}\)z-4.
Перенесем слагаемые с z в одну сторону, а числа в другую:
\(\frac{4}{5}\)z - \(\frac{16}{5}\)z = -4 - 2 - \(\frac{10}{3}\).
\(\frac{4 - 16}{5}\)z = -6 - \(\frac{10}{3}\).
-\(\frac{12}{5}\)z = -\(\frac{18}{3}\) - \(\frac{10}{3}\).
-\(\frac{12}{5}\)z = -\(\frac{28}{3}\).
z = -\(\frac{28}{3}\) : -\(\frac{12}{5}\).
z = \(\frac{28}{3}\) * \(\frac{5}{12}\).
z = \(\frac{7}{3}\) * \(\frac{5}{3}\).
z = \(\frac{35}{9}\).
Ответ: z = \(\frac{35}{9}\) = 3 \(\frac{8}{9}\)