Решение:
Сначала определим все необходимые промежуточные множества:
- A∪B = {9, 8, 7, 6, 5, 4, 3, 2, 1, 0}
- A∪C = {7, 6, 5, 4, 3, 2, 1, 0, -1, -2, -3}
- A∪D = {7, 6, 5, 4, 3, 2, 1, 0}
- B∪C = {9, 8, 7, 6, 5, 4, 3, 2, 1, 0, -1, -2, -3}
- B∪D = {9, 8, 7, 6, 5, 4, 3, 2}
- C∪D = {6, 5, 4, 3, 2, 1, 0, -1, -2, -3}
- A∩B = {7, 6, 5, 4, 3}
- A∩C = {4, 3, 2, 1, 0}
- A∩D = {6, 5, 4, 3, 2}
- B∩C = {4, 3, 2}
- B∩D = {6, 5, 4, 3, 2}
- C∩D = {4, 3, 2}
- A\B = {0, 1}
- A\C = {7, 6, 5}
- B\D = {9, 8, 7}
Теперь можно ответить на вопросы:
- a) A∪B∪C∪D = {9, 8, 7, 6, 5, 4, 3, 2, 1, 0, -1, -2, -3}
- б) A∩B∩C∩D = { }
- в) (A∩B)∪(C∩D) = {7, 6, 5, 4, 3, 2}
- г) (A∩B)∩(C∪D) = {6, 5, 4, 3}
- д) (A\B)∩(A\C) = { }
- e) (A\B)∪(A\C) = {7, 6, 5, 1, 0}
- ж) (A∩C)\(A∩B) = {1, 0}
- з) (A∪D)\(B∩D) = {7, 1, 0}
- и) (A∪C)\(B\D) = {7, 6, 5, 4, 3, 2, 1, 0, -1, -2, -3}