B) (3a*b*)3 .(18a*b)2 (3a²b) =

в) $$\frac{(3a^9b^8)^3 \cdot (18a^4b^9)^2}{(3a^5b^6)^7} = \frac{3^3a^{27}b^{24} \cdot 18^2a^8b^{18}}{3^7a^{35}b^{42}} = \frac{27a^{27}b^{24} \cdot 324a^8b^{18}}{2187a^{35}b^{42}} = \frac{27 \cdot 324}{2187} \cdot \frac{a^{27+8}b^{24+18}}{a^{35}b^{42}} = \frac{8748}{2187} \cdot \frac{a^{35}b^{42}}{a^{35}b^{42}} = 4 \cdot 1 = 4$$

Ответ: 4