B) $$\sqrt[5]{4\sqrt[3]{k^2l^5}}$$;

B) $$\sqrt[5]{4\sqrt[3]{k^2l^5}}$$;

$$\sqrt[5]{4\sqrt[3]{k^2l^5}} = \sqrt[5]{4\cdot k^{\frac{2}{3}}l^{\frac{5}{3}}} = \sqrt[5]{2^2\cdot k^{\frac{2}{3}}l^{\frac{5}{3}}} = 2^{\frac{2}{5}}k^{\frac{2}{3*5}}l^{\frac{5}{3*5}} = 2^{\frac{2}{5}}k^{\frac{2}{15}}l^{\frac{1}{3}} = \sqrt[5]{2^2}\cdot \sqrt[15]{k^2}\cdot \sqrt[3]{l} = \sqrt[5]{4}\cdot \sqrt[15]{k^2}\cdot \sqrt[3]{l}$$

Ответ: $$\sqrt[5]{4}\cdot \sqrt[15]{k^2}\cdot \sqrt[3]{l}$$