arcsin(-\(\frac{\sqrt{2}}{2}\)) = -\(\frac{\pi}{4}\), так как sin(-\(\frac{\pi}{4}\)) = -\(\frac{\sqrt{2}}{2}\)
arccos \(\frac{1}{2}\) = \(\frac{\pi}{3}\), так как cos \(\frac{\pi}{3}\) = \(\frac{1}{2}\)
arcsin(-\(\frac{\sqrt{2}}{2}\)) + arccos \(\frac{1}{2}\) = -\(\frac{\pi}{4}\) + \(\frac{\pi}{3}\) = \(\frac{-\3\pi + 4\pi}{12}\) = \(\frac{\pi}{12}\)
Ответ: \(\frac{\pi}{12}\)