16) arccos (-\(\frac{\sqrt{2}}{2}\)) - arcsin (-1);

arccos(-\(\frac{\sqrt{2}}{2}\)) = \(\frac{3\pi}{4}\), так как cos \(\frac{3\pi}{4}\) = -\(\frac{\sqrt{2}}{2}\)

arcsin(-1) = -\(\frac{\pi}{2}\), так как sin(-\(\frac{\pi}{2}\)) = -1

arccos(-\(\frac{\sqrt{2}}{2}\)) - arcsin (-1) = \(\frac{3\pi}{4}\) - (-\(\frac{\pi}{2}\)) = \(\frac{3\pi}{4}\) + \(\frac{\pi}{2}\) = \(\frac{3\pi + 2\pi}{4}\) = \(\frac{5\pi}{4}\)

Ответ: \(\frac{5\pi}{4}\)