15.36. a) $$\frac{-2^4}{3} - \frac{2^4}{9}$$; б) $$\frac{(-2)^2}{2^3} - \frac{5^2}{4}$$; в) $$\frac{(-2)^3}{5} - \frac{3}{2^2}$$; г) $$\frac{14}{3^2} - \frac{2^4}{(-3)^3}$$.

a) $$\frac{-2^4}{3} - \frac{2^4}{9} = \frac{-16}{3} - \frac{16}{9} = \frac{-16 \cdot 3}{3 \cdot 3} - \frac{16}{9} = \frac{-48}{9} - \frac{16}{9} = \frac{-48-16}{9} = \frac{-64}{9} = -7\frac{1}{9}$$

Ответ: $$-7\frac{1}{9}$$

б) $$\frac{(-2)^2}{2^3} - \frac{5^2}{4} = \frac{4}{8} - \frac{25}{4} = \frac{1}{2} - \frac{25}{4} = \frac{1 \cdot 2}{2 \cdot 2} - \frac{25}{4} = \frac{2}{4} - \frac{25}{4} = \frac{2-25}{4} = \frac{-23}{4} = -5\frac{3}{4}$$

Ответ: $$-5\frac{3}{4}$$

в) $$\frac{(-2)^3}{5} - \frac{3}{2^2} = \frac{-8}{5} - \frac{3}{4} = \frac{-8 \cdot 4}{5 \cdot 4} - \frac{3 \cdot 5}{4 \cdot 5} = \frac{-32}{20} - \frac{15}{20} = \frac{-32 - 15}{20} = \frac{-47}{20} = -2\frac{7}{20}$$

Ответ: $$-2\frac{7}{20}$$

г) $$\frac{14}{3^2} - \frac{2^4}{(-3)^3} = \frac{14}{9} - \frac{16}{-27} = \frac{14}{9} + \frac{16}{27} = \frac{14 \cdot 3}{9 \cdot 3} + \frac{16}{27} = \frac{42}{27} + \frac{16}{27} = \frac{42+16}{27} = \frac{58}{27} = 2\frac{4}{27}$$

Ответ: $$2\frac{4}{27}$$