A) 4\frac{2}{3}+1\frac{1}{3}·3-9\frac{1}{6}

А) Выполним действия:

1) $$1\frac{1}{3} \cdot 3 = \frac{4}{3} \cdot 3 = 4$$

2) $$4\frac{2}{3} + 4 = 8\frac{2}{3}$$

3) $$9\frac{1}{6} = \frac{9 \cdot 6 + 1}{6} = \frac{55}{6}$$

4) $$8\frac{2}{3} - 9\frac{1}{6} = \frac{8\cdot3 + 2}{3} - \frac{55}{6} = \frac{26}{3} - \frac{55}{6} = \frac{26 \cdot 2}{3 \cdot 2} - \frac{55}{6} = \frac{52}{6} - \frac{55}{6} = -\frac{3}{6} = -\frac{1}{2} = -0,5$$

Ответ: -0,5