933. Решите уравнение:

a) $$(2x-3)^2-2x(4 + 2x) = 11$$. $$4x^2 - 12x + 9 - 8x - 4x^2 = 11$$. $$-20x + 9 = 11$$. $$-20x = 2$$. $$x = -\frac{2}{20} = -\frac{1}{10}$$.

б) $$(4x - 3)(3 + 4x) - 2x(x - 1) = 0$$. $$(4x-3)(4x+3) - 2x^2 + 2x = 0$$. $$16x^2 - 9 - 2x^2 + 2x = 0$$. $$14x^2 + 2x - 9 = 0$$. $$x = \frac{-2 \pm \sqrt{4 - 4(14)(-9)}}{2(14)} = \frac{-2 \pm \sqrt{4 + 504}}{28} = \frac{-2 \pm \sqrt{508}}{28} = \frac{-2 \pm 2\sqrt{127}}{28} = \frac{-1 \pm \sqrt{127}}{14}$$.