9. $(11\frac{1}{6}:3\frac{3}{8})+(3\frac{3}{4}-1\frac{13}{20})\cdot2\frac{1}{3}$

Question

$Фото задания: 9. $(11\frac{1}{6}:3\frac{3}{8})+(3\frac{3}{4}-1\frac{13}{20})\cdot2\frac{1}{3}$$ Фото задания

Accepted Answer

$11\frac{1}{6}:3\frac{3}{8}=\frac{67}{6}:\frac{27}{8}=\frac{268}{81}$.

$3\frac{3}{4}-1\frac{13}{20}=\frac{15}{4}-\frac{33}{20}=\frac{21}{10}$.

$\frac{21}{10}\cdot\frac{7}{3}=\frac{49}{10}$.

$\frac{268}{81}+\frac{49}{10}=\frac{6649}{810}$.

Ответ: $\frac{6649}{810}$.

9. \((11\frac{1}{6}:3\frac{3}{8})+(3\frac{3}{4}-1\frac{13}{20})\cdot2\frac{1}{3}\)