2. $(7\frac{2}{6}-3\frac{9}{10}):(2\frac{1}{3}+1\frac{5}{9})\cdot4\frac{1}{6}$

Question

$Фото задания: 2. $(7\frac{2}{6}-3\frac{9}{10}):(2\frac{1}{3}+1\frac{5}{9})\cdot4\frac{1}{6}$$ Фото задания

Accepted Answer

$7\frac{2}{6}-3\frac{9}{10}=\frac{22}{3}-\frac{39}{10}=\frac{103}{30}$.

$2\frac{1}{3}+1\frac{5}{9}=\frac{7}{3}+\frac{14}{9}=\frac{35}{9}$.

$\frac{103}{30}:\frac{35}{9}\cdot\frac{25}{6}=\frac{103}{30}\cdot\frac{9}{35}\cdot\frac{25}{6}=\frac{103}{28}$.

Ответ: $\frac{103}{28}$.

2. \((7\frac{2}{6}-3\frac{9}{10}):(2\frac{1}{3}+1\frac{5}{9})\cdot4\frac{1}{6}\)