6. \(\left(\left(\frac{3}{8}-\frac{5}{6}\right):\frac{3}{4}+\left(-\frac{3}{8}-0,35\right):1,45\right)\cdot0,02\)

Преобразуем десятичные дроби: \(0,35=\frac{7}{20}\), \(1,45=\frac{29}{20}\), \(0,02=\frac{1}{50}\).

\[\left(\frac{3}{8}-\frac{5}{6}\right):\frac{3}{4}=\left(-\frac{11}{24}\right)\cdot\frac{4}{3}=-\frac{11}{18}.\]

\[\left(-\frac{3}{8}-0,35\right):1,45=\left(-\frac{3}{8}-\frac{7}{20}\right):\frac{29}{20}=\left(-\frac{29}{40}\right)\cdot\frac{20}{29}=-\frac{1}{2}.\]

\[\left(-\frac{11}{18}-\frac{1}{2}\right)\cdot\frac{1}{50}=\left(-\frac{11}{18}-\frac{9}{18}\right)\cdot\frac{1}{50}=-\frac{10}{18}\cdot\frac{1}{50}=-\frac{1}{45}.\]

Ответ: \(-\frac{1}{45}\).