4. \(\left(\frac{2,5+3\frac{1}{3}}{2,5-1\frac{1}{3}}\right):\left(\frac{4,6-2\frac{1}{3}}{-4\frac{7}{15}-2\frac{1}{3}}\right)\cdot\left(\frac{0,05}{\frac{1}{7}-0,125}-0,2\right)\)

Преобразуем десятичные дроби в обыкновенные:

\(2,5=\frac{5}{2}\), \(4,6=\frac{23}{5}\), \(0,05=\frac{1}{20}\), \(0,125=\frac{1}{8}\), \(0,2=\frac{1}{5}\).

\[\frac{2,5+3\frac{1}{3}}{2,5-1\frac{1}{3}}=\frac{\frac{5}{2}+\frac{10}{3}}{\frac{5}{2}-\frac{4}{3}}=\frac{\frac{35}{6}}{\frac{7}{6}}=5.\]

\[\frac{4,6-2\frac{1}{3}}{-4\frac{7}{15}-2\frac{1}{3}}=\frac{\frac{23}{5}-\frac{7}{3}}{-\frac{67}{15}-\frac{7}{3}}=\frac{\frac{34}{15}}{-\frac{102}{15}}=-\frac{1}{3}.\]

\[5:\left(-\frac{1}{3}\right)=-15.\]

\[\frac{0,05}{\frac{1}{7}-0,125}-0,2=\frac{\frac{1}{20}}{\frac{1}{7}-\frac{1}{8}}-\frac{1}{5}=\frac{\frac{1}{20}}{\frac{1}{56}}-\frac{1}{5}=\frac{14}{5}-\frac{1}{5}=\frac{13}{5}.\]

\[-15\cdot\frac{13}{5}=-39.\]

Ответ: \(-39\).