Решение:
- \(\frac{1}{3} - \frac{1}{8} = \frac{1 \cdot 8 - 1 \cdot 3}{24} = \frac{8-3}{24} = \frac{5}{24}\)
- \(\frac{7}{20} - \frac{5}{30} = \frac{7 \cdot 3 - 5 \cdot 2}{60} = \frac{21-10}{60} = \frac{11}{60}\)
- \(4\frac{1}{2} - \frac{1}{9} = \frac{9}{2} - \frac{1}{9} = \frac{9 \cdot 9 - 1 \cdot 2}{18} = \frac{81-2}{18} = \frac{79}{18} = 4\frac{7}{18}\)
- \(8\frac{5}{12} - \frac{1}{43} = \frac{8 \cdot 12 + 5}{12} - \frac{1}{43} = \frac{101}{12} - \frac{1}{43} = \frac{101 \cdot 43 - 1 \cdot 12}{12 \cdot 43} = \frac{4343 - 12}{516} = \frac{4331}{516} = 8\frac{173}{516}\)
- \(9\frac{7}{9} - \frac{4}{6} = 9\frac{7}{9} - \frac{2}{3} = \frac{9 \cdot 9 + 7}{9} - \frac{2 \cdot 3}{9} = \frac{81+7 - 6}{9} = \frac{82}{9} = 9\frac{1}{9}\)
- \(6\frac{7}{32} - \frac{11}{48} = \frac{6 \cdot 32 + 7}{32} - \frac{11}{48} = \frac{192+7}{32} - \frac{11}{48} = \frac{199}{32} - \frac{11}{48} = \frac{199 \cdot 3 - 11 \cdot 2}{96} = \frac{597 - 22}{96} = \frac{575}{96} = 5\frac{95}{96}\)
Ответ: 1) \(\frac{5}{24}\); 2) \(\frac{11}{60}\); 3) \(4\frac{7}{18}\); 4) \(8\frac{173}{516}\); 5) \(9\frac{1}{9}\); 6) \(5\frac{95}{96}\).