Вопрос:

52. Выполните вычитание: 1) 1/3 - 1/8; 2) 7/20 - 5/30; 3) 4 1/2 - 1/9; 4) 8 5/12 - 1/43; 5) 9 7/9 - 4/6; 6) 6 7/32 - 11/48.

Ответ:

Решение:

  1. \(\frac{1}{3} - \frac{1}{8} = \frac{1 \cdot 8 - 1 \cdot 3}{24} = \frac{8-3}{24} = \frac{5}{24}\)
  2. \(\frac{7}{20} - \frac{5}{30} = \frac{7 \cdot 3 - 5 \cdot 2}{60} = \frac{21-10}{60} = \frac{11}{60}\)
  3. \(4\frac{1}{2} - \frac{1}{9} = \frac{9}{2} - \frac{1}{9} = \frac{9 \cdot 9 - 1 \cdot 2}{18} = \frac{81-2}{18} = \frac{79}{18} = 4\frac{7}{18}\)
  4. \(8\frac{5}{12} - \frac{1}{43} = \frac{8 \cdot 12 + 5}{12} - \frac{1}{43} = \frac{101}{12} - \frac{1}{43} = \frac{101 \cdot 43 - 1 \cdot 12}{12 \cdot 43} = \frac{4343 - 12}{516} = \frac{4331}{516} = 8\frac{173}{516}\)
  5. \(9\frac{7}{9} - \frac{4}{6} = 9\frac{7}{9} - \frac{2}{3} = \frac{9 \cdot 9 + 7}{9} - \frac{2 \cdot 3}{9} = \frac{81+7 - 6}{9} = \frac{82}{9} = 9\frac{1}{9}\)
  6. \(6\frac{7}{32} - \frac{11}{48} = \frac{6 \cdot 32 + 7}{32} - \frac{11}{48} = \frac{192+7}{32} - \frac{11}{48} = \frac{199}{32} - \frac{11}{48} = \frac{199 \cdot 3 - 11 \cdot 2}{96} = \frac{597 - 22}{96} = \frac{575}{96} = 5\frac{95}{96}\)

Ответ: 1) \(\frac{5}{24}\); 2) \(\frac{11}{60}\); 3) \(4\frac{7}{18}\); 4) \(8\frac{173}{516}\); 5) \(9\frac{1}{9}\); 6) \(5\frac{95}{96}\).

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