Решение:
- \( 9\frac{1}{4} \cdot 8\frac{1}{5} - 2\frac{1}{12} = \frac{37}{4} \cdot \frac{41}{5} - \frac{25}{12} = \frac{1517}{20} - \frac{25}{12} = \frac{4551}{60} - \frac{125}{60} = \frac{4426}{60} = \frac{2213}{30} = 73\frac{23}{30} \)
- \( 1\frac{3}{22} \cdot \left(2\frac{5}{6} + 3\frac{5}{7}\right) \cdot \frac{3}{5} = \frac{25}{22} \cdot \left(\frac{17}{6} + \frac{26}{7}\right) \cdot \frac{3}{5} = \frac{25}{22} \cdot \left(\frac{119+156}{42}\right) \cdot \frac{3}{5} = \frac{25}{22} \cdot \frac{275}{42} \cdot \frac{3}{5} = \frac{5}{22} \cdot \frac{275}{42} \cdot \frac{3}{1} = \frac{5}{22} \cdot \frac{275}{14} \cdot 1 = \frac{5}{2} \cdot \frac{25}{14} = \frac{125}{28} = 4\frac{13}{28} \)
Ответ: 1) \( 73\frac{23}{30} \) 2) \( 4\frac{13}{28} \)