Решение:
- \(3(5a+4)-11a = 15a+12-11a = 4a+12\)
- \(3a(7-b)-7(b-3a) = 21a-3ab-7b+21a = 42a-3ab-7b\)
- \((3x-11)-0,2-5(0,4-0,3x) = 3x-11-0,2-2+1,5x = (3x+1,5x) + (-11-0,2-2) = 4,5x - 13,2\)
- \(-3,5(3a-2b)+2(1,3a-b) = -10,5a+7b+2,6a-2b = (-10,5a+2,6a) + (7b-2b) = -7,9a+5b\)
Ответ: 1) 4a+12; 2) 42a-3ab-7b; 3) 4,5x - 13,2; 4) -7,9a+5b.