2. Вычислите: 1) (2ⁱ⁴⁸ - (-⁲⁷⁵ⁱ⁲)) : (-3⁴⁳ + 9⁴⁳) : (-13);

Решение:

1. \(\( \frac{13}{48} - (-\frac{2}{12}) \) : \(-\frac{3}{4} + \frac{9}{4}\) : (-13) = \(\frac{13}{48} + \frac{2}{12}\) : \(\frac{6}{4}\) : (-13) = \(\frac{13}{48} + \frac{8}{48}\) : \(\frac{3}{2}\) : (-13) = \(\frac{21}{48}\) : \(\frac{3}{2}\) : (-13) = \(\frac{7}{16}\) : \(\frac{3}{2}\) : (-13) = \(\frac{7}{16} \frac{2}{3}\) : (-13) = \(\frac{7}{24}\) : (-13) = \(\frac{7}{24} : (-13) = \frac{7}{24 (-13)} = \frac{7}{-312} = -\frac{7}{312}\)

Ответ: -\(\frac{7}{312}\).