4. \(\left(\frac{10}{8}+\frac{11}{12}\right):\frac{9}{48}\)

\[\left(\frac{10}{8}+\frac{11}{12}\right):\frac{9}{48}=\left(\frac{5}{4}+\frac{11}{12}\right)\cdot\frac{48}{9}\]

\[=\left(\frac{15}{12}+\frac{11}{12}\right)\cdot\frac{16}{3}=\frac{26}{12}\cdot\frac{16}{3}=\frac{13}{6}\cdot\frac{16}{3}=\frac{104}{9}\]

Ответ: \(\frac{104}{9}=11\frac{5}{9}\)