4. \( 1 \frac{32}{49} : (5 \frac{15}{49} - 3 \frac{13}{14}) + \frac{2}{3} \cdot (4,35 - 4,68 : 2,6) + 2,94 \cdot \frac{5}{7} \)

Решение:

1. \( 1 \frac{32}{49} = \frac{49+32}{49} = \frac{81}{49} \)
2. \( 5 \frac{15}{49} = \frac{5 \cdot 49 + 15}{49} = \frac{245+15}{49} = \frac{260}{49} \)
3. \( 3 \frac{13}{14} = \frac{3 \cdot 14 + 13}{14} = \frac{42+13}{14} = \frac{55}{14} \)
4. \( \frac{260}{49} - \frac{55}{14} = \frac{260 \cdot 2}{98} - \frac{55 \cdot 7}{98} = \frac{520 - 385}{98} = \frac{135}{98} \)
5. \( \frac{81}{49} : \frac{135}{98} = \frac{81}{49} \cdot \frac{98}{135} = \frac{81 \cdot 2}{135} = \frac{162}{135} = \frac{6}{5} = 1,2 \)
6. \( 4,68 : 2,6 = 1,8 \)
7. \( 4,35 - 1,8 = 2,55 \)
8. \( \frac{2}{3} \cdot 2,55 = \frac{2}{3} \cdot \frac{255}{100} = \frac{2 \cdot 85}{100} = \frac{170}{100} = 1,7 \)
9. \( 2,94 \cdot \frac{5}{7} = \frac{294}{100} \cdot \frac{5}{7} = \frac{42 \cdot 5}{100} = \frac{210}{100} = 2,1 \)
10. \( 1,2 + 1,7 + 2,1 = 5,0 \)

Ответ: 5