Вопрос:

38. Вычислите: \(\frac{46}{50}:\left(\frac{7}{20}-\frac{11}{15}\right)+3\cdot1\frac{11}{15}\).

Ответ:

\[\frac{46}{50}=\frac{23}{25},\qquad \frac{7}{20}-\frac{11}{15}=\frac{21-44}{60}=-\frac{23}{60}.\]

\[\frac{23}{25}:\left(-\frac{23}{60}\right)=-\frac{12}{5}.\]

\[3\cdot1\frac{11}{15}=3\cdot\frac{26}{15}=\frac{26}{5}.\]

\[-\frac{12}{5}+\frac{26}{5}=\frac{14}{5}.\]

Ответ: \(\frac{14}{5}\).