37) 310 (33)3 316 =

$$\frac{3^{10} \cdot (3^3)^3}{3^{16}} = \frac{3^{10} \cdot 3^{3 \cdot 3}}{3^{16}} = \frac{3^{10} \cdot 3^9}{3^{16}} = \frac{3^{10 + 9}}{3^{16}} = \frac{3^{19}}{3^{16}} = 3^{19 - 16} = 3^3 = 27$$

Ответ: 27