Ответ:
Приводим дроби к знаменателю 42: \(\frac{1}{21}=\frac{2}{42}\), \(\frac{1}{3}=\frac{14}{42}\), \(\frac{5}{6}=\frac{35}{42}\).
\(20\frac{1}{21}+9\frac{1}{3}+10\frac{5}{6}=39+\frac{2+14+35}{42}=39+\frac{51}{42}=40\frac{3}{42}=40\frac{1}{14}\).
Ответ: \(40\frac{1}{14}\).
