Ответ:
а) \(1\frac{1}{9}-\frac{2}{3}=1\frac{1}{9}-\frac{6}{9}=\frac{4}{9}\).
б) \(12\frac{3}{8}-6\frac{7}{20}=12\frac{15}{40}-6\frac{14}{40}=6\frac{1}{40}\).
в) \(4\frac{5}{21}+5\frac{3}{14}=9+\frac{10}{42}+\frac{9}{42}=9\frac{19}{42}\).
г) \(\frac{3}{10}\cdot\frac{20}{21}=\frac{2}{7}\).
е) \(9\frac{1}{3}\cdot1\frac{1}{8}=\frac{28}{3}\cdot\frac{9}{8}=\frac{21}{2}=10\frac{1}{2}\).
ж) \(\frac{9}{14}:\frac{18}{35}=\frac{9}{14}\cdot\frac{35}{18}=\frac{5}{4}=1\frac{1}{4}\).
з) \(3\frac{1}{5}:2\frac{2}{15}=\frac{16}{5}:\frac{32}{15}=\frac{16}{5}\cdot\frac{15}{32}=\frac{3}{2}=1\frac{1}{2}\).
Ответ: а) \(\frac{4}{9}\); б) \(6\frac{1}{40}\); в) \(9\frac{19}{42}\); г) \(\frac{2}{7}\); е) \(10\frac{1}{2}\); ж) \(1\frac{1}{4}\); з) \(1\frac{1}{2}\).
