- \[\frac{17}{60}-\frac{7}{30}+\frac{1}{40}=\frac{34}{120}-\frac{28}{120}+\frac{3}{120}=\frac{9}{120}=\frac{3}{40}.\]
- \[10-4\frac{6}{13}=5\frac{7}{13}.\]
- \[1\frac{3}{4}+2\frac{5}{6}=3+\frac{9}{12}+\frac{10}{12}=3\frac{19}{12}=4\frac{7}{12}.\]
- \[3\frac{4}{15}+5\frac{11}{12}=8+\frac{16}{60}+\frac{55}{60}=9\frac{11}{60}.\]
- \[6\frac{1}{6}-3\frac{4}{9}=5\frac{7}{6}-3\frac{4}{9}=2+\frac{21}{18}-\frac{8}{18}=3\frac{13}{18}.\]
Ответ: а) \(\frac{3}{40}\); б) \(5\frac{7}{13}\); в) \(4\frac{7}{12}\); г) \(9\frac{11}{60}\); д) \(3\frac{13}{18}\).