42-ге көбейтеміз: \[3(9x+4)-2(12x+7)<7(7x+4)-21(x-2)-252.\] \[27x+12-24x-14<49x+28-21x+42-252.\] \[3x-2<28x-182\Rightarrow180<25x\Rightarrow x>\frac{36}{5}=7.2.\]
Жауабы: \((7.2;+\infty)\).