1107. Раскройте скобки и приведите подобные слагаемые: 1) \(\frac{2}{3} \(-\frac{3}{8}x + 6\) - \(\frac{3}{7}\) \(28 - \frac{7}{12}x\); 2) -\(\frac{2}{9}\) \(2,7x - 1\frac{1}{2}y\) - 1\(\frac{1}{6}\) \(2,4x - 1\frac{5}{7}y\).

Решение:

1. • \( \frac{2}{3} \cdot (-\frac{3}{8}x) + \frac{2}{3} \cdot 6 - \frac{3}{7} \cdot 28 + \frac{3}{7} \cdot \frac{7}{12}x = -\frac{2}{8}x + 4 - 12 + \frac{3}{12}x = -\frac{1}{4}x - 8 + \frac{1}{4}x = -8 \)
   • \( -\frac{2}{9} \cdot 2,7x - \frac{2}{9} \cdot (-\frac{3}{2}y) - \frac{7}{6} \cdot \frac{24}{10}x + \frac{7}{6} \cdot \frac{12}{7}y = -\frac{2}{9} \cdot \frac{27}{10}x + \frac{2}{9} \cdot \frac{3}{2}y - \frac{7 \cdot 4}{10}x + \frac{12}{6}y = -\frac{1}{1} \cdot \frac{3}{5}x + \frac{1}{3}y - \frac{14}{5}x + 2y = -\frac{3}{5}x + \frac{1}{3}y - \frac{28}{10}x + 2y \)
   • \( -\frac{3}{5}x - \frac{14}{5}x + \frac{1}{3}y + 2y = (-\frac{3}{5} - \frac{14}{5})x + (\frac{1}{3} + \frac{6}{3})y = -\frac{17}{5}x + \frac{7}{3}y \)

Ответ: 1) -8; 2) \(-\frac{17}{5}x + \frac{7}{3}y\).