Решение:
- 1 : \(\frac{1}{7}\) = \(1 \cdot \frac{7}{1}\) = 7
- 1 : 0,3 = 1 : \(\frac{3}{10}\) = \(1 \cdot \frac{10}{3}\) = \(\frac{10}{3}\) = \(3\frac{1}{3}\)
- \(\frac{7}{7} : \frac{7}{8}\) = \(\frac{7}{7} \cdot \frac{8}{7}\) = \(\frac{8}{7}\) = \(1\frac{1}{7}\)
- \(\frac{6}{49} : \frac{18}{35}\) = \(\frac{6}{49} \cdot \frac{35}{18}\) = \(\frac{6 \cdot 35}{49 \cdot 18}\) = \(\frac{1 \cdot 5}{7 \cdot 3}\) = \(\frac{5}{21}\)
- 5 : \(\frac{2}{9}\) = \(5 \cdot \frac{9}{2}\) = \(\frac{45}{2}\) = \(22\frac{1}{2}\)
- \(\frac{11}{16} : 33\) = \(\frac{11}{16} \cdot \frac{1}{33}\) = \(\frac{11}{16 \cdot 33}\) = \(\frac{1}{16 \cdot 3}\) = \(\frac{1}{48}\)
Ответ: 1) 7; 2) \(3\frac{1}{3}\); 3) \(1\frac{1}{7}\); 4) \(\frac{5}{21}\); 5) \(22\frac{1}{2}\); 6) \(\frac{1}{48}\).