1. Вычислите: 1) \(\frac{3}{9}\cdot\frac{9}{3}\); 2) \(\frac{7}{12}+\frac{7}{9}\); 3) \(\frac{7}{35}-\frac{1}{10}\).

1. \(\frac{3}{9}\cdot\frac{9}{3}=1\).
2. \(\frac{7}{12}+\frac{7}{9}=\frac{21}{36}+\frac{28}{36}=\frac{49}{36}=1\frac{13}{36}\).
3. \(\frac{7}{35}-\frac{1}{10}=\frac{1}{5}-\frac{1}{10}=\frac{1}{10}\).

Ответ: 1) 1; 2) \(1\frac{13}{36}\); 3) \(\frac{1}{10}\).