1) 6\(\frac{1}{14}\) - \(\frac{1}{7}\); 3) 6\(\frac{2}{6}\) - 2\(\frac{1}{6}\); 5) 8\(\frac{1}{8}\) - 5\(\frac{1}{6}\); 2) 8\(\frac{9}{40}\) - 6\(\frac{13}{50}\); 4) 9\(\frac{7}{34}\) - 1\(\frac{29}{102}\); 6) 7\(\frac{13}{36}\) - 3\(\frac{25}{54}\);

Решение:

1. \( 6\frac{1}{14} - \frac{1}{7} = 6\frac{1}{14} - \frac{2}{14} = 5\frac{15}{14} - \frac{2}{14} = 5\frac{13}{14} \)
2. \( 8\frac{9}{40} - 6\frac{13}{50} = 8\frac{45}{200} - 6\frac{52}{200} = 7\frac{245}{200} - 6\frac{52}{200} = 1\frac{193}{200} \)
3. \( 6\frac{2}{6} - 2\frac{1}{6} = 4\frac{1}{6} \)
4. \( 9\frac{7}{34} - 1\frac{29}{102} = 9\frac{21}{102} - 1\frac{29}{102} = 8\frac{123}{102} - 1\frac{29}{102} = 7\frac{94}{102} = 7\frac{47}{51} \)
5. \( 8\frac{1}{8} - 5\frac{1}{6} = 8\frac{3}{24} - 5\frac{4}{24} = 7\frac{27}{24} - 5\frac{4}{24} = 2\frac{23}{24} \)
6. \( 7\frac{13}{36} - 3\frac{25}{54} = 7\frac{39}{108} - 3\frac{50}{108} = 6\frac{147}{108} - 3\frac{50}{108} = 3\frac{97}{108} \)

Ответ: 1) \(5\frac{13}{14}\) 2) \(1\frac{193}{200}\) 3) \(4\frac{1}{6}\) 4) \(7\frac{47}{51}\) 5) \(2\frac{23}{24}\) 6) \(3\frac{97}{108}\)